-16t^2-44t+10=0

Solution for -16t^2-44t+10=0 equation:

-16t^2-44t+10=0

a = -16; b = -44; c = +10;
Δ = b2-4ac
Δ = -442-4·(-16)·10
Δ = 2576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2576}=\sqrt{16*161}=\sqrt{16}*\sqrt{161}=4\sqrt{161}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-4\sqrt{161}}{2*-16}=\frac{44-4\sqrt{161}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+4\sqrt{161}}{2*-16}=\frac{44+4\sqrt{161}}{-32}
$